the roots of the equation 2 x² + (p + 1) x + Q equals to 0 are 1 and 3, where P and Q are the constants find the values of p and q
Answers
Answered by
1
Answer:
now
1+3=-[p+1]/2
8=-p-1
p=-9
1*3=q/2
q=6
Step-by-step explanation:
Similar questions