Math, asked by nanjishnu, 3 months ago

The roots of the equation 2x^2-6x+7=0 are

* real and equal and rational

real and equal and irrational

real and equal

*imaginary

Answers

Answered by biligiri

1

Step-by-step explanation:

a= 2, b = -6 and c = 7

D = b² - 4ac

=> D = (-6)² - 4*2*7

=> D = 36 - 56

=> D = -20

as D < 0, imaginary roots

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