Question

The roots of the equation √2x2 - 2x - √3 = 0 are:​

Answer 1

Step-by-step explanation:

Ur answer is in the above attachment

Answer 2

The roots of the equation are

$x= \frac{-2 + \sqrt{4+4\sqrt{6} }}{2\sqrt{2} }\\x= \frac{-2 - \sqrt{4+4\sqrt{6} }}{2\sqrt{2} }$

Step-by-step explanation:

P(x) = $\sqrt{2}x^2 -2x-\sqrt{3}$

using the quadratic formula to find the roots of the equation

then

$D = b^2 - 4ac \\here \\a = \sqrt{2} \\b = -2\\c= -\sqrt{3} \\then , \\D = (-2)^2 \times - 4 \sqrt{2}\times -\sqrt{3}\\ D = 4+ 4\sqrt{6}$

if b² - 4ac > 0 then roots are given by

$x = \frac{-b \pm \sqrt{D}}{2a}\\x= \frac{-2 \pm \sqrt{4+4\sqrt{6} }}{2\sqrt{2} }$

hence , the roots of the equation are

 $x= \frac{-2 + \sqrt{4+4\sqrt{6} }}{2\sqrt{2} }\\x= \frac{-2 - \sqrt{4+4\sqrt{6} }}{2\sqrt{2} }$

#Learn more:

The nature of root of quadritic equation 2x2-2x+1=0

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