the roots of the equation 3x2 square + (6 + 4 a) x+ 8a=0 are equal to zero are equal find the value of a
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3x²+(6+4a)x+8a=0
3x²+6x+4ax+8a=0
3x(x+2)+4a(x+2)=0
(3x+4a)(x+2)=0
x=-4a/3 or x=-2
put values of x in given equation one by one second one is not possible
3x²+6x+4ax+8a=0
3x(x+2)+4a(x+2)=0
(3x+4a)(x+2)=0
x=-4a/3 or x=-2
put values of x in given equation one by one second one is not possible
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