Question

the roots of the equation 4x^2 + 8ax + 4a^2 = 0 are​

Answer 1

Answer:

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Answer 2

Answer:

4x^2+8ax+4a^2=0

let us write,

by taking 4 as common,

4(x^2+a^2)+8ax=0

taking 4 as common again and send to R.H.S

(x^2+a^2)+2ax=0

so it is in form of (x+a)^2

hence,(x+a)^2=0

(x+a)(x+a)=0

hence roots are x=-a,-a