The roots of the equation 6x^2+bx+c are "alpha" and "1/alpha", then the value of 'c' in this equation is? Pls help dont spam
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: Product of roots= alpha×1/alpha= c/a(according to the formula) So 1= c/a( here alpha multiplied with 1/alpha will give 1 and we have a= 6 given in the question) so 1=c/6 this gives c=6
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