Question

The roots of the equation 6x^2-x-2=0 is:

Answer 1

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☞ Your Answer = -1/2 or 2/3

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$\huge\sf\blue{Given}$

✭ P(x) = 6x²-x-2

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$\huge\sf\gray{To \:Find}$

◈ Itz Roots?

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Now Finding the Roots,

➝ $\sf 6x^2-x-2 = 0$

➝ $\sf 6x^2-4x+3x-2 = 0$

➝ $\sf 2x(3x-2)+1(3x-2)$

➝ $\sf\red{(2x+1)(3x-2)}$

Hence the Roots of the Equation are,

≫ $\sf\orange{-\frac{1}{2} \ or \ \frac{2}{3}}$

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