Math, asked by clerlinbeypi14, 7 months ago

the roots of the equation 7x²+x-1=0 are real and distinct
1) true
2) false​

Answers

Answered by deepaksarathy027
1

Answer:

2)FALSE

Step-by-step explanation:

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Answered by EnchantedBoy
1

Question:

The roots of the equation 7x^{2}+x-1=0 are real and distinct roots

1)true

2)false

Answer:

1)true

Given:

→An equation is given , 7x^{2}+x-1=0

Step-by-step explanation:

7x^{2}+x-1=0

It is in the form of, ax^{2}+bx-c=0

Here, a = 7 ,b = 1 ,c=-1

We know that,

Δ=b^{2}-4ac

⇒Δ=(1)^{2}-4×7×-1

⇒Δ=1+28=29

Now,<u>Δ=29\ge0</u>

So, the Equation will be Real and distinct roots

More information:

Here, b^{2}-4ac called as the Discrimination (which is denoted by Δ)of the quadratic equation , decides the nature of roots ad follows,

Δ\ge0⇒Real and unequal roots

Δ=0⇒Real and equal roots

Δ∠0⇒No real roots.

Hope it helps,

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