Math, asked by pr287212, 5 months ago

The roots of the equation a×a×q×q×x×x-p2 =0 will be​

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Answered by Anonymous
4

Answer:

2

Step-by-step explanation:

Required Answer:-

Given equation

Given equation x

Given equation x 2

Given equation x 2 +px+q

Given equation x 2 +px+qAlso, given p,q are the roots of the equation.

Given equation x 2 +px+qAlso, given p,q are the roots of the equation.p+q=−p

Given equation x 2 +px+qAlso, given p,q are the roots of the equation.p+q=−p 2p=−q .....(1)

Given equation x 2 +px+qAlso, given p,q are the roots of the equation.p+q=−p 2p=−q .....(1)And pq=q

Given equation x 2 +px+qAlso, given p,q are the roots of the equation.p+q=−p 2p=−q .....(1)And pq=qq(p−1)=0

Given equation x 2 +px+qAlso, given p,q are the roots of the equation.p+q=−p 2p=−q .....(1)And pq=qq(p−1)=0⇒q=0 or p=1

Given equation x 2 +px+qAlso, given p,q are the roots of the equation.p+q=−p 2p=−q .....(1)And pq=qq(p−1)=0⇒q=0 or p=1So, by (1), q=0⇒p=0

Given equation x 2 +px+qAlso, given p,q are the roots of the equation.p+q=−p 2p=−q .....(1)And pq=qq(p−1)=0⇒q=0 or p=1So, by (1), q=0⇒p=0 Hence, the values of p are 0,1.

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