Question

The roots of the equation a(b-c) x²+b(c-a) x+c(a-b) =0 (a≠b≠c≠0) are? ​

Answer 1

Answer:

a(b-c)+b(c-a)+c(a-b)=0

➡️the roots are

1,c(a-b)/a(b-c)

I hope it's help you✌️

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Answer 2

$\huge\mathfrak\red{\underline\orange{\underline\purple{Solution}}}$

→ a(b-c) +b(c-a) +c(a-b) =0

→ Therefore,The roots are 1,c(a-b)/a(b-c)

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