Question

The roots of the equation (ab-1)x²+(a+b)x-ab=0 are always
1)Real
2)Equal
3)Complex
4) Cannot be determined

Plz explain how to find the answer.​

Answer 1

Answer:

ANSWER

x2+(a−b)x+(1−a−b)=0...(i)

For given condition,

⇒D>0⇒(a−b)2−4(1−a−b)>0

⇒b2−2(a−2)b+(a2+4a−4)>0

⇒(a−2)2−(a2+4a−4)<0⇒−8a+8<0⇒a>1

Step-by-step explanation:

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