Question

The roots of the equation (ab – 1)x2 + (a + b)x -
ab = 0 are always
(1) Real
(2) Equal
(3) Complex
(4) Cannot be determined
​

Answer 1

$\huge\bigstar\sf\red{Answer:}$

$\sf{Here,}$

$\sf{a=(ab-1), \ b=(a+b) \ c=-ab}$

$\sf{b^{2}-4ac=(a+b)^{2}-4(ab-1)(-ab)}$

$\sf{=a^{2}+b^{2}+2ab+4ab(ab-1)}$

$\sf{=a^{2}+b^{2}+4a^{2}b^{2}-2ab}$

$\sf{4) \ Cannot \ be \ determined \ is \ right \ answer.}$

Answer 2

Answer:

(a) real

can be the answer