Math, asked by santoshkrgaya2020, 9 months ago

The roots of the equation (ab – 1)x2 + (a + b)x -
ab = 0 are always
(1) Real
(2) Equal
(3) Complex
(4) Cannot be determined

Answers

Answered by Anonymous
1

\huge\bigstar\sf\red{Answer:}

\sf{Here,}

\sf{a=(ab-1), \ b=(a+b) \ c=-ab}

\sf{b^{2}-4ac=(a+b)^{2}-4(ab-1)(-ab)}

\sf{=a^{2}+b^{2}+2ab+4ab(ab-1)}

\sf{=a^{2}+b^{2}+4a^{2}b^{2}-2ab}

\sf{4) \ Cannot \ be \ determined \ is \ right \ answer.}

Answered by rishavgautam0001
0

Answer:

(a) real

can be the answer

Similar questions