Question

The roots of the equation (b-c)x^2+(c-a)x+(a-b)=0 are

Answer 1

Answer:

1 , a - b/b - c

Step-by-step explanation:

(b-c)x² + (c-a)x + (a-b)=0  

=>  (b-c)x² + [-(b-c)}x +{-(a-b)]x + (a-b) = 0

=> (b-c)x (x - 1)  - (a - b)(x - 1) = 0

=> (x - 1)[(b-c)x - (a-b)] = 0

=> x = 1 x = a - b/b - c.

Thus the factors are 1, a - b/b - c