Math, asked by akshitask153, 1 year ago

The roots of the equation (b-c)x^2 + (c-a)x + (a-b) =0 are
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Answered by sherin23
0
♥️HEY MATE♥️
.HERE IS THE ANSWER TO YOUR QUESTION....

If the roots of the equation (b-c) x^2+(c-a) x+(a-b) =0 are equal, then how can I prove that 2b=a+c?

(b-c)x²+(c-a)x+(a-b)=0

Comparing with quadratic equation

Ax²+Bx+C=0

A=(b-c),B=c-a,C=a-b

Discriminate when roots are equal

D=B²-4AC=0

D=(c-a)²−4(b-c)(a-b)=0

D=(c²+a²−2ac)-4(ba-ac-b²+bc)=0

D=c²+a²−2ac-4ab+4ac+4b²-4bc=0

c²+a²+2ac-4b(a+c)+4b²=0

(a+c)²-4b(a+c)+4b²=0

[(a+c)-2b]²=0

a+c=2b

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akshitask153: Tysm for answering but in the question I don't have any prooving part...it's only to find roots
Answered by goyhdarft1234
0

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