Question

the roots of the equation is​

Answer 1

Finding roots of given Quadratic equation by

Factorisation method:

(b+c)x²-(a+b+c)x+a=0

Splitting the middle term,

we get,

(b+c)x²-ax-(b+c)x+a = 0

=>x[(b+c)x-a]-1[(b+c)x-a]=0

=> [(b+c)x-a][x-1]=0

=> (b+c)x - a = 0 or x-1 = 0

=> x = a/(b+c) or x = 1

••••