The roots of the equation (x+1)²-4|x-1| +3=0
1. Form an A.P 2. Form a G.P
3. Form an H.P 4. Do not form any progression
Answers
Answer:
the roots of equation are 3+0 this is answer
Given : Equation (x+1)²-4|x-1| +3=0
To Find : The roots of the equation Form an
AP
GP
HP
Do not form any progression
Solution:
(x+1)²-4|x-1| +3=0
x ≥ 1
=> (x+1)²-4(x-1) +3=0
=> x² + 2x + 1 - 4x + 4 + 3 = 0
=> x² - 2x + 8 = 0
Roots will be imaginary
x < 1
(x+1)²-4(1-x)+3=0
=> x² + 2x + 1 - 4 + 4x + 3 = 0
=> x² + 6x = 0
=> x( x + 6) = 0
=> x = 0 , x = - 6
Hence there are only two roots and not enough to define Series
However they can not form HP or GP at all because of one root being 0
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