the roots of the equation x^2+10x+13=0 are
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Answered by
1
x² + 10x + 13 = 0
use formula ,
x = { -b ±√(b²-4ac)}/2a
then,
x = { -10±√(100-52)}/2
= -5±2√3
use formula ,
x = { -b ±√(b²-4ac)}/2a
then,
x = { -10±√(100-52)}/2
= -5±2√3
Answered by
0
compare given equation with ax²+bx +c=0
a=1 , b= 10 , c=13
D = b² - 4ac =(10)² - 4*1*13= 100 -52 = 48
√D = √48 = √4*4*3 = 4√3
x= (-b + or - √D)/2a
x=( -10 +4√3)/2 or x= (-10 -4√3)/2
x=-5+2√3 or x= -5 -2√3
a=1 , b= 10 , c=13
D = b² - 4ac =(10)² - 4*1*13= 100 -52 = 48
√D = √48 = √4*4*3 = 4√3
x= (-b + or - √D)/2a
x=( -10 +4√3)/2 or x= (-10 -4√3)/2
x=-5+2√3 or x= -5 -2√3
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