Question

the roots of the equation x^2 +(2p-1)x+p^2=0,are real if?​

Answer 1

Answer:

Step-by-step explanation:

If detrminant i.e. b² - 4ac is greater than or equal to zero

In this case b = ( 2p - 1 )

a = 1 and c = p²

So (2p - 1)² - 4(1)(p²) should be greater than or equal to zero

So 4p²+1-4p - 4p² greater than or equal to zero

So 1- 4p is greater than or equal to zero

So p≤1/4

P belongs to (-∞,1/4)