Math, asked by Hrlp, 11 months ago

The roots of the equation (x-a)(x-b)+ (x-b)(x-c)+(x-c)(x-a)=0 are ​

Answers

Answered by Anonymous
4

Given ,

discriminant is 4(a+b+c)^2 -12(ab+bc+ac) =0

So, the roots are real

Hope it helps

Answered by royal171gmailcom
0
the answer is correct or not
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