Question

The roots of the equation
(x -- b)(x - c) + (x - a)(x - 2) + (x -- a)(x - b) = 0
are distinct real number if
(a) a= b not equal to c
(b) b= c not equal to a
(c) c= a not equal to b
(d) a= b= c​

Answer 1

Step-by-step explanation:

check for option (d) we get real roots but same roots and in any other case answer will be same but nothing can be said about the nature of the root...

Try eliminating the options