Math, asked by DBgaming, 5 hours ago

The roots of the equation (x-b)(x-c)+(x-c)(x-a)+(x-a)(x-b)=0are always​

Answers

Answered by sreeramnarayanan2
1

Answer:

Both the roots of the equation (x-b)(x-c)+(x-a)(x-c)+(x-a)(x-b)=0 are always a. positive b. real c. negative d. none of these

Answered by mahantadilip70
1

Answer:

-bx-cx+ (-ax) +(-ax) -bx

Step-by-step explanation:

positive / negative

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