The roots of the equation (x-b)(x-c)+(x-c)(x-a)+(x-a)(x-b)=0are always
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Answered by
1
Answer:
Both the roots of the equation (x-b)(x-c)+(x-a)(x-c)+(x-a)(x-b)=0 are always a. positive b. real c. negative d. none of these
Answered by
1
Answer:
-bx-cx+ (-ax) +(-ax) -bx
Step-by-step explanation:
positive / negative
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