the roots of the equation x minus 3 whole square is equal to 3
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(x-3)^2 =3
x2 - 6x + 9 = 3
x2 - 6x +9 - 3 = 0
x2 - 6x + 6 = 0
We will try to solve the equation by Quadratic Formula Method
[a = 1; b = (-6); c = 6]
D = b2 - 4ac = (-6)^2 - 4(1)(6) = 36 -24 = 12
x = (-b ± √D)/2a
x = [-(-6) ± √12)/2(1)
x = (6 + 2√3)/2
x = 2(3+√3)/2
x = 3+√3
x = (6 - 2√3)/2
x = 2(3-√3)/2
x = 3-√3
Hope it helps please mark as brainliest
x2 - 6x + 9 = 3
x2 - 6x +9 - 3 = 0
x2 - 6x + 6 = 0
We will try to solve the equation by Quadratic Formula Method
[a = 1; b = (-6); c = 6]
D = b2 - 4ac = (-6)^2 - 4(1)(6) = 36 -24 = 12
x = (-b ± √D)/2a
x = [-(-6) ± √12)/2(1)
x = (6 + 2√3)/2
x = 2(3+√3)/2
x = 3+√3
x = (6 - 2√3)/2
x = 2(3-√3)/2
x = 3-√3
Hope it helps please mark as brainliest
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