Math, asked by shivani125, 1 year ago

the roots of the equation x power 2/3+xpower1/3-2=0

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Answered by Anonymous
0
[tex] x^{ \frac{2}{3} } + x^{ \frac{1}{3} } - 2 = 0 \\ x^{ \frac{2}{3} } + 2x^{ \frac{1}{3} } - x^{ \frac{1}{3} } - 2 = 0 \\ x^{ \frac{1}{3} }( x^{ \frac{1}{3} }+2) - 1 ( x^{ \frac{1}{3} }+2) = 0 \\ ( x^{ \frac{1}{3} } -1)( x^{ \frac{1}{3} }+2) = 0 \\ x^{ \frac{1}{3} } = 1 (or) x^{ \frac{1}{3} } = -2 \\ x = 1 (or) x = -8 [/tex]

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