The roots of the equation x²-(√2+3√2)x+6=0 arex²-(√2+3√2)X+6=0 are
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Answer:
X=√2 ,3√2
Step-by-step explanation:
X^2 -√2X-3√2X+6=0
X(X-√2)-3√2(X-√2)=0
(X-3√2) (X-√2)=0
X-3√2=0
X=3√2
X-√2=0
X=√2
X=√2 ,3√2
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