Question

The roots of the equation x2 +(2p-1)x + p2 =0 are real if

Answer 1

given roots are equal so b^2-4ac=0
(2p-1)^2-4*1*p^2=0
4p^2-4p+1-4p^2=0
-4p+1=0
p=1/4

Answer 2

Answer:

p = 1/4

Step-by-step explanation:

Compare the equation by

ax^2 + bx + c =0

a= 1 ,b = (2p-1) & c = p^2

Numbers are real roots of a equation when

b^2-4ac = 0