Question

the roots of the equation x2 -3x=0 is​

Answer 1

Answer:

Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

2−3=0

x^{2}-3x=0x2−3x=0

=1

a={\color{#c92786}{1}}a=1

=−3

b={\color{#e8710a}{-3}}b=−3

=0

c={\color{#129eaf}{0}}c=0

=−(−3)±(−3)2−4⋅1⋅0√2⋅1

Step-by-step explanation:

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Answer 2

Answer:

Using -b+_√(b²-4ac)÷2a

a=1 b=-3 c=0

-(-3)+_√(-3²-4×1×0)÷2×1

3+_√(9-0)÷2

(3+_√9)÷2

(3+_3)÷2

When postive

3+3÷2

6/2

3

And, when negative

(3-3)÷2

0/2

0

Hence, 3 and 0 are roots of the given equation.

Hope it helps you!