The roots of the equation x² − 3x − m (m + 3) = 0, where m is a constant, are
A. m, m + 3
B. − m, m + 3
C. m, − (m + 3)
D. −m, − (m + 3)
Answers
Answered by
11
Solution :
x² -3x - m(m+3) = 0
=> x² + mx - ( m+3)x - m(m+3) = 0
=> x( x + m )-(m+3)( x + m ) = 0
=> ( x + m )[ x - ( m + 3 ) ] = 0
Therefore ,
x + m = 0 or x - ( m+3 ) = 0
=> x = - m , x = m+3
Option ( B ) is correct.
•••••
x² -3x - m(m+3) = 0
=> x² + mx - ( m+3)x - m(m+3) = 0
=> x( x + m )-(m+3)( x + m ) = 0
=> ( x + m )[ x - ( m + 3 ) ] = 0
Therefore ,
x + m = 0 or x - ( m+3 ) = 0
=> x = - m , x = m+3
Option ( B ) is correct.
•••••
Answered by
5
x²-3x-m(m+3)=0
or, x²-{(m+3)- m}x -m(m+3)=0
or, x²-(m+3)x +mx-m(m+3)=0
0r, x[x-(m+3)]+m[x-(m+3)]=0
or, [x-(m+3)][x+m]=0
now
[x-(m+3)]=0 or, x=m+3 and x +m= 0 or, x= -m
SO (B.) IS THE RIGHT ANSWER
or, x²-{(m+3)- m}x -m(m+3)=0
or, x²-(m+3)x +mx-m(m+3)=0
0r, x[x-(m+3)]+m[x-(m+3)]=0
or, [x-(m+3)][x+m]=0
now
[x-(m+3)]=0 or, x=m+3 and x +m= 0 or, x= -m
SO (B.) IS THE RIGHT ANSWER
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