Question

The roots of the equation x2 - under root 3 x -x + under root 3 = 0 are​

Answer 1

Answer:

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Step-by-step explanation:

Answer:Step(k+2)x²-kx+6 (k+ 2)3²-k(3)+6=0 (k+2)9-3k+6=0 9k+18-3k+6=0 6k+24=0 6k=-24 K=-24/6 k=-4 -by-step ...