Question

the roots of the equation(x²-x-6)=x+2​

Answer 1

${x}^{2} - x - 6 = x + 2 \\ => {x}^{2} - x - x - 6 - 2 = 0 \\ => {x}^{2} - 2x - 8 = 0 \\ = > {x}^{2} - (4 - 2)x - 8 = 0 \\ => {x}^{2} - 4x + 2x - 8 = 0 \\ => x(x - 4) + 2(x - 4) = 0 \\ => (x + 2)(x - 4) = 0 \\so \\ x + 2 = 0 \: \: \: \: \: \: \: \: \: \: \: \: \: or \: \: \: \: \: \: \: \: \: \: \: \: x - 4 = 0\\ => x = - 2 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: => x = 4 \\ required \: roots \: are \: - 2 \: and \: 4$

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Answer 2

Answer:

Answer is in the attachment