Question

The roots of the equation x2+ x + p(p+1) = 0, where p is a constant, are

a) p, p+1 b) –p, p+1 c) p, -(p+1) d) –p, -(p+1​

Answer 1

Answer:

${x}^{2} + x - p(p + 1) = 0 \\ {x}^{2} + (p + 1)x - px - p(p + 1) = 0$

$x(x + p + 1) - p(x + p + 1) = 0 \\ (x + p + 1)(x - p) = 0 \\ x = p \: \: or \: \: - (p + 1)$

option C correct