Question

The roots of the equation xsquare+ax+b=0 are one less than the roots of the equation xsquare+bx+a=0.Find the value of a+b.

Answer 1

Answer:

Step-by-step explanation:

Let say the common root is y. Then y should satisfy both the equations given in the question. Hence they may be written as

y2+ay+b=0…….(1)

y2+by+a=0……..(2)

Subtract (1) from (2)

y(a−b)+(b−a)=0

y(a−b)=(a−b)

y=1

Hence placing the value of y in (1) we have

1+a+b=0

a+b=−1