Question

The roots of the following quadratic equation are: *
2x^2+x+4=0 are positive or negative​

Answer 1

Answer:

2x2 + x + 4 = 0

⇒ 2x2 + x = -4

Dividing the equation by 2, we get

⇒ x2 + 1 / 2x = -2

⇒ x2 + 2 × x × 1 / 4 = -2

By adding (1 / 4)2 to both sides of the equation, we get

⇒ (x)2 + 2 × x × 1 / 4 + (1 / 4)2 = (1 / 4)2 – 2

⇒ (x + 1 / 4)2 = 1 / 16 – 2

⇒ (x + 1 / 4)2 = -31 / 16

The square root of negative number is imaginary, therefore, there is no real root for the given equation.