Question

the roots of the following quadratic equation are real and equal, find k. y^2 +ky+12=0​

Answer 1

Step-by-step explanation:

3y

2

+ky+12=0

The roots of the given quadratic equation are real and equal. So, the discriminant will be 0.

b

2

−4ac=0

⇒k

2

−4×3×12=0

⇒k

2

−144=0

⇒k

2

=144

⇒k=±12