The roots of the quadratic eq uation √3 x² - 2√2 x -2√3=0 are
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P(x) =√3x²-2x-√3
√3x²-3x+x-√3=0
√3x(x-√3) +1 ( x-√3)
(x-√3)(√3x+1)
x-3=0 √3x+1=0
x= 3 √3x= -1= x= -1/√3
the roots of the equation are 3 and -1√3
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answer is in the attachment
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