Question

The roots of the quadratic equation

2x^2-x-6=0 are

Answer 1

Answer:

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Step-by-step explanation:

2x^2-(4-3)x-6=0

2x^2-4x+3x-6=0

2x(x-2) + 3(x-2)=0

(2x+3) (x-2)

2x+3=0

2x=-3

x=-3/2

OR

x=2