Question

The roots of the quadratic equation 2x 2 −x+ 8 1 ​ =0 are​

Answer 1

Answer:

2x

2

−x+

8

1

=0

16x^2-8x+1=016x

2

−8x+1=0

16x^2-4x-4x+1=016x

2

−4x−4x+1=0

4x(4x-1)-1(4x-1)=04x(4x−1)−1(4x−1)=0

(4x-1)(4x-1)=0(4x−1)(4x−1)=0

x = \frac{1}[4},\frac{1}{4}

Hence the solution is x = \frac{1}[4},\frac{1}{4}