Question

The roots of the quadratic equation (3x - 5)(x + 3) = 0 are:
(A) 3 -3
(B) -5, 3
(C)5/3, -3
(D) 5, -3​

Answer 1

for zeroes......

( x + 3 )( 3x - 5 ) = 0

case i

( x + 3 ) = 0

=> x = -3

case ii

( 3x - 5 ) = 0

=> 3x = 5

=> x = 5/3

hence, option c is correct........

Answer 2

Answer:

(c) 5/3,-3 is the correct option.

Step-by-step explanation:

(3x-5) (x+3)=0 is given in the question....

now first of all we will solve the first bracket i.e.,

(3x-5)=0

3x= 5 (when 5 will come from left to right side its sign will get change from (-) to (+)..

now,x=5/3( because 3 was multiplying with x on left side so when it came to the right side it got divided by 5 i.e.,5/3

[first bracket solved ]

now we will solve the second bracket i.e.,

(x+3)=0

x=-3 (because when 3 will come from left to right side it will change from (+) to (-) ..

[ second bracket solved]

in this way, we got the two roots of the above quadratic equation i.e., [ 5/3,-3]

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