Question

the roots of the quadratic equation 3x2-6x=0​

Answer 1

Answer:

ansswwerrrrrr Jef/?996

Answer 2

Step-by-step explanation:

=−±2−4√2

x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}x=2a−b±b2−4ac

Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

32−6=0

3x^{2}-6x=03x2−6x=0

=3

a={\color{#c92786}{3}}a=3

=−6

b={\color{#e8710a}{-6}}b=−6

=0

c={\color{#129eaf}{0}}c=0

=−(−6)±(−6)2−4⋅3⋅0√2⋅3

x=\frac{-({\color{#e8710a}{-6}}) \pm \sqrt{({\color{#e8710a}{-6}})^{2}-4 \cdot {\color{#c92786}{3}} \cdot {\color{#129eaf}{0}}}}{2 \cdot {\color{#c92786}{3}}}x=2⋅3−(−6)±(−6)2−4⋅3⋅0

2