Question

The roots of the quadratic equation 4y2 = 16y are​

Answer 1

Answer:

4y² = 16y

4y² - 16y = 0

We know that, a quadratic equation is of the form ax² + bx + c =0

Now,

a= 4

b = -16

c = 0

x = -b±√(b²-4ac)/2a

= -(-16)±√(-16² - 4×4×0)/2×4

= 16±√-16²/8

= 16+16/8 , 16-16/8

= 32/8 , 0/8

= 4 , 0

So the roots are 4 and 0.