Question

the roots of the quadratic equation 6 x square minus x minus 2 = 0 ​

Answer 1

$\huge{\bf{\underline{\underline{\pink{ANSWER}}}}}$

$6 {x}^{2} - x - 2 = 0$

$\implies \: 6 {x}^{2} - 4x + 3x - 2 = 0$

$\implies2x(3x - 2) + 1(3x - 2)$

$\implies \: (3x - 2)(2x + 1) = 0$

$\implies \: x = \frac{2}{3} \: or \: x = \frac{1}{2}$

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