The roots of the quadratic equation 6x -5x+1=0 are:
Kanthisri:
Is it 6x-5x+1=0 or 6x^2 -5x+1=0??
Answers
Answered by
0
6x^2-2x-3x+1
2x (3x-1)-1 (3x+1)
(2x-1) (3x+1)
=>2x-1=0
x=1/2
=>3x+1=0
x=-1/3
2x (3x-1)-1 (3x+1)
(2x-1) (3x+1)
=>2x-1=0
x=1/2
=>3x+1=0
x=-1/3
Answered by
1
6x^2-5x+1=0
6x^2-3x-2x+1=0
3x(2x-1)-1(2x-1)=0
(3x-1)(2x-1)=0
3x=1 or 2x=1
x=1/3 or 1/2
6x^2-3x-2x+1=0
3x(2x-1)-1(2x-1)=0
(3x-1)(2x-1)=0
3x=1 or 2x=1
x=1/3 or 1/2
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