Question

. The roots of the quadratic equation 6x² – x – 2 = 0 are​

Answer 1

Answer:

Step-by-step explanation:

6x² - x - 2 = 0

⇒ 6x² - 4x + 3x - 2 = 0

⇒ 2x(3x - 2) +1(3x - 2) = 0

⇒ (2x+1)(3x - 2) = 0

so either  (3x - 2) = 0 or  (2x+1) = 0

x = 2/3 or -1/2 ANSWER

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Answer 2

Answer:

$\sqrt{6 {x}^{2} - x - 2 } = 0$

$= \sqrt{6} \times x - \sqrt{x - 2}$

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