Question

the roots of the quadratic equation c(a -b)x^2 + a(b -c)x + b(c - a) = 0 are equal , then ​

Answer 1

Answer:ab- ac +4 = 0

Step-by-step explanation:

In this case, D will be 0.

As, D = $b^{2} - 4ac$

=> $b^{2} = 4ac$

$=> a^{2} (b-c^{2} ) = 4[c(a-b)] [b(c-a)]\\\\=> a^{2} (b-c^{2} ) = 4 [a(c-b)]\\=>a(b-c) = -4$