Question

the roots of the quadratic equation is real and equal find K x²-2(k+1)x+k²​

Answer 1

Answer:

Given x

2

−2(k+1)x+k

2

=0 has real and equal roots

As we know that

for a quadratic equation to have real and equal roots ,discriminant should be zero

⟹(−2(k+1))

2

−4(1)(k

2

)=0

⟹(k+1)

2

−k

2

=0

⟹2k+1=0

⟹k=−

2

1