Question

The roots of the quadratic equation:
(x+1)(x+2)+(x-1)(x-2)=3(x-1)(x+2)​

Answer 1

Answer:

Given equation (x−2)(x+1)=(x−1)(x+3)

To find whether the given equation is a quadratic equation or not

Sol:

(x−2)(x+1)=(x−1)(x+3)

⟹x

2

+x−2x−2=x

2

+3x−x−3

⟹x

2

−x

2

+x−2x−3x+x−2+3=0

⟹−3x+1=0

This is not a quadratic equation as an equation of degree two is called a quadratic equation.

And, a polynomial when equated to zero or some value becomes an equation.