Question

the roots of the quadratic equation x+2x-15=0 are
a)5 & -3
b) -5 & 3
c) -5 & -3
d)5 & 3

plss pls ans ​

Answer 1

${\huge{\boxed{\sf{\red{Quéstion:-}}}}}$

the roots of the quadratic equation x²+2x-15=0 are:-

${\huge{\boxed{\sf{\green{Answér:-}}}}}$

${x}^{2} + 2x - 15 = 0 \\ \\ {x}^{2} - 5x + 3x - 15 \\ \\ x(x - 5) + 3(x - 5) \\ \\ (x - 5)(x + 3) \\ \\ \\ ... \\ \\ x - 5 \\ {\boxed{x = 5}} \\ \\ x + 3 \\ {\boxed{x = - 3}}$

SO , THE ROOTS TO EQUATION ARE :- 5, -3

OPTION - a)5 & -3

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Answer 2

Step-by-step explanation:

a)-5 and 3

Substitute x = -5

L.H.S

= x²+2x-15

= (-5)²+2×(-5)-15

= 25-10-15

= 25-25

= 0

Hence L.H.S = R.H.S.

Therefore, -5 is a root of the given quadratic equation.

Now,Substitute x = 3

L.H.S

= x²+2x-15

= (3)²+2×3-15

= 9+6-15

= 15-15

= 0

Hence,L.H.S = R.H.S.

Therefore, 3 is a root of the given quadratic equation.

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