Question

the roots of the quadratic equation (x-√5) (x+2) are ?
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Answer 1

Answer:

ANSWER

Given equation is x

2

−3

5x

+10=0

We know that

Roots of quadratic equation ax

2

+bx+c=0 are given by

x=

2a

−b±

b

2

−4ac

or x=

2a

−b±

D

∴D=b

2

−4ac

⇒D=(−3

5

)

2

−4(1)(10)

⇒D=45−40=5

⇒

D

=

5

Now, x=

2a

−b±

D

⇒x=

2

3

5

±

5

⇒x

1

=

2

3

5

+

5

and x

2

=

2

3

5

−

5

⇒x

1

=

2

4

5

and x

2

=

2

2

5

⇒x

1

=2

5

and x

2

=

5

Hence, the roots of the given equation are 2

5

and

5