Question

the roots of the quadratic equation x minus b into x minus b + x minus b into x minus 3 + X - 3 into x minus 3 equal to zero or equal then show that equal to b equal to C​

Answer 1

Answer:

3x^2 -xb +b^2 -3x +3b -6x +9

Step-by-step explanation:

(x-b)(x-b)+(x-b)(x-3)+(x-3)(x-3) =0

(x-b)^2 +[x^2-x(b+3) +(3b) +(x-3)^2 =0

[(x)^2 -2(x)(b) +(b)^2] +[x^2-xb-3x+3b] +[x^2 -2(x)(3) +3^2] =0

(x^2 -2xb +b^2) +(x^2 -xb -3x +3b) +(x^2 -6x +3^2) =0

(x^2 +x^2 +x^2) -(2xb +xb) +b^2 -3x +3b -6x +9 =0

3x^2 -xb +b^2 -3x +3b -6x +9 =0

hope it will help you

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Answer 2

Answer:

Mark me as the brainliest

Step-by-step explanation:

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