Question

. The roots of the quadratic equation x2-1=0 are​

Answer 1

Answer:

The roots of the quadratic equation $x^{2} -1$ are $+1,-1.$

Step-by-step explanation:

• Step 1:

Write the quadratic equation : $x^{2} -1$

• Step 2 :

Factorise the above quadratic equation into linear factors.

• Step 3 :

By using the identity

                        $a^{2} -b^{2} = (a-b)(a+b)$

By comparing,

$a = x , b = 1$

we get,

$x^{2} -1$  $= (x-1)(x+1)$

• Step 4 :

To calculate the roots of quadratic equation, equate each linear factor to zero.            

•        $x-1 = 0$                                        

            $x= 1$  

and                                          

•   $x+1 = 0$

$x = -1$

Therefore, the roots of the quadratic equation $x^{2} -1$ are $+1,-1.$

#SPJ2

Answer 2

Answer:

The roots of the quadratic equation are  ±1

Step-by-step explanation:

Given quadratic equation is x²-1=0

To find,

The roots of the quadratic equation

Recall the formula

a² - b² = (a+b)(a-b)

Solution:

Given equation is  x²-1=0 ⇒ x²-1²=0

Applying the formula a² - b² = (a+b)(a-b) we get,

(x+1)(x-1) = 0

(x+1) = 0, (x-1) = 0

x = +1 , x = -1

x = ±1,

Hence the roots of the quadratic equation x²-1=0 are  ±1

#SPJ5