Math, asked by kavyanjalinarsale, 6 months ago

The roots of the quadratic
equation
x2 - 6x + k = 0 are real and equal, find​

Answers

Answered by sehejarora75
0

Answer:

The value of k = 9/2 = 4.5

If the roots of a quadratic equation are real and equal then

Discriminant(b^2 - 4ac) of  Quadratic equation is zero.

It is given a quadratic equation

2x2- 6x + k = 0,

the roots of  are real and equal.

Therefore Discriminant of  Quadratic equation is zero.

b^2 - 4ac =0

The coefficients of  2x2- 6x + k = 0,

a = 2

b = -6

c = k

To find the value of k

b^2 - 4ac =0

(-6)^2 - 4 x 2x k = 0

8k = 36

k = 36/8 = 9 /2 = 4.5

Step-by-step explanation:

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